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5y^2-14y-24=0
a = 5; b = -14; c = -24;
Δ = b2-4ac
Δ = -142-4·5·(-24)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{676}=26$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-26}{2*5}=\frac{-12}{10} =-1+1/5 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+26}{2*5}=\frac{40}{10} =4 $
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